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-
...**2
y2 = x**3
plt.plot(x, y1,
linewidth=0.5,
linestyle='--',
color='b',
marker='o',
markersize=10,
markerfacecolor='red')
plt.plot(...
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...;rand1=(60*one-15000*(0-(0.002/sqrt(2.))*sign(rand(Size_load_power(1,2),1)-0.5*one).*log(1*one-2*abs((rand(Size_load_power(1,2),1))-0.5*one))))/100;% % for kk=1:Size_load_power(1,2)% if rand1(kk,1)<0%  ...
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...0AE30Mellanox® Passive Copper Cable, IB HDR, up to 200Gb/s, QSFP56, LSZH, 0.5M, black pultab, 30AWGHDRMCP7H50-H001R30Mellanox® Passive Copper Hybrid cable, IB HDR 200Gb/s to 2x100Gb/s, QSFP56 to 2xQSFP56, LSZH, colored pulltabs, 1m, 30AWGHDRMCP7H50-H01AR30Mellanox® Passive Copper Hybrid cable, IB...
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... //TL0重置函数
cp1++;
if(cp1 >= 250) //0.5秒
{
cp1 = 0;
flash = ~flash; //产生闪烁变量
cp2++;
if(cp2 >= 5)
{
cp2 = 0;
conv = ~conv; //产生交替显示变量
}
}
if(conv == 1)
{
...
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...o buscode voltage angle pd qd pg qg]busdata = [ 1 1 1.06 0 0 0 0 0;2 0 1 0 0.5 0.2 0 0;3 0 1 0 0.4 0.3 0 0;4 0 1 0 0.3 0.1 0 0;]%linedata = [startbus endbus r x shunt-y]linedata = [1 2 2 8.0 0;1 3 1 4.0 0;2 3 0.666 2.664 0;2 4 1 4.0 0;3 4 2 8.0 0;] n1 =linedata(:,1);%lineda...
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... transformer% (Xtrans = j0.15) and two parallel transmission lines (Xl1 = j0.5, Xl2 = 0.093)% assuming lossless conditions.Xtrans = 0.15; %[ohm] impedance of step-up transformerXl1 = 0.5; %[ohm] impedance of line 1 Xl2 = 0.93; %[...
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...
ctx.fillStyle = "rgba(0,0,200,0.5)";
//ctx.fillRect(30,30,55,50);
ctx.strokeRect(30,30,55,50);
ctx.clearRect(15,15,20,25);
...
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...,&i);bonus1=100000*0.1;bonus2=bonus1+100000*0.75;bonus4=bonus2+200000*0.5;bonus6=bonus4+200000*0.3;bonus10=bonus6+400000*0.15; if(i〈=100000) bonus=i*0.1; else if(i〈=200000) bonus=bonus1+(i-100000)*0.075; else if(i〈=400000) bonus=bonu...