-
-
... case 0x28: // 4行2列，13
key=0xa1;
break;
case 0x48: // 4行3列，14
key=0x86;
break;
case 0x88: // 3行4列，15
key=0x8e;
break;
default:break;
}
}
/* 主程序 */
void main()
{
uchar i = 0;
key=0xc0;
w...
-
-
...dMenuIn(relatedNode);
45. }
46.
47. function foldMenuIn(targetNode) {
48. if (!targetNode) return;
49. var newCurrentlyOpenedMenus = new Array();
50. for (var i=0;i<currentlyOpenedMenus.length;i++) {
51. if (!containsElement(currentlyOpenedMenus[i],targetNode)) {
52. currentlyOpe...
-
-
...向18B20的暂存写上、下限温度分别为128，-55
Write_OneChar(0x48); //向18B20的rom中写数据
while(1);
//{
// temp = read_temprom; //从DS18B20中读取的温度给变量temp
//}
}
-
-
...,0x66,0x6D,0x7D,0x07,0x7F,0x6F};//1~~~~9段选码
uchar code S[8]={0X28,0X48,0X18,0X48,0X82,0X84,0X81,0X84};//交通信号灯控制代码
/**********************延时子程序************************/
void Delay(uchar a)
{
uchar i;
i=a;
while(i--){;}
}
/*****************显示子...
-
-
...，UDP端口4791用于RoCEv2通信。# cat ~/rdma_traffic.txt ...14:48:23.007280 IP (tos 0x0, ttl 64, id5066, offset 0, flags [DF], proto UDP (17), length 308)1.1.6.2.49153 > 1.1.5.2.4791: [no cksum]UDP, length 2800x0000: 248a 0780 5401 e41d 2df2 a45c 81000006 $...T...-..\....0x0010: 0800 4...
-
-
... dancedata[] = {54,15,12,12,87,95,65,45,-89,-88,-54,-54,54,68,-45,-65,-65,-48,101,121,115,117,19,
-98,-100,-21,-114,-101,-24,-98,95,102,102,100,130,30,10,-90,-120,87,102,103,105,109,104,-30,-102,-104,-106,110,100,
54,15,12,12,87,95,65,45,-89,-88,-54,-54,-98,95,102,102,100,130,30,10,-90,-120,87,102...
-
-
...度,上电时显示+125.00C
unsigned char TempBuffer0[17]={0x54,0x48,0x3a,0x2b,0x31,0x32,0x35,0x20,
0x54,0x4c,0x3a,0x2b,0x31,0x32,0x34,0x43,'\0'};
//显示温度上下限,上电时显示TH:+125 TL:+124C
unsigned char code dotcode[4]={0,25,50,75};
/***因显示分辨...
-
-
...sp; img.draw_cross(max_blob1.cx(), max_blob1.cy(),color = (176,48,96)) p1.low() p2.low() p3.high() print('1')  ...
-
-
...0x11,0x09,0x17};static char R[]={0x72,0x66,0x6C,0x42,0x5C,0x4E,0x50,0x44,0x48,0x74};static int ORDER[10][13]={1,1,1,1,1,1,-1,2,2,2,2,2,2, 1,1,0,1,0,0,...
-
-
...y);}==============================================================【程序48】题目：宏#define命令练习(3) 1.程序分析：2.程序源代码：#define LAG 〉#define SMA 〈#define EQ ==#include “stdio.h“void main(){ int i=10;int j=20;if(i LAG j)printf(“\40: %d larger than %d ...
