-
-
...clude <fstream>
#include <cstring>
using namespace std;
int adminView();
int studentView();
int studentLogin();
int checkCredentials(string userName, string password);
int getAllStudentsbyRollNo();
int deleteAllStudents();
int deleteStudentbyRollno();
int checkListOfStudent...
-
-
### 1.c++中，声明const int i,是在哪个阶段做到 i只可读的？（A）+ A.编译+ B.链接+ C.运行+ D.以上都不对解析：const用来说明所定义的变量是只读的。 这些在编译期间完成，编译器可能使用常数直接替换掉对此变量的引用。### 2.对于...
-
-
...nclude<iostream>
#include"NetTopo.h"
using namespace std;
//const int DefaultVertices=200; //默认的拓扑的最大顶点数
const int inf=1000;//最大权值
//构造函数
NetTopo::NetTopo(int sz)
{
maxVertices=sz;//设置最大顶点数
numVertic...
-
-
...o in pixels
* @height: total height of the active video in lines
* @interlaced: Interlaced or progressive
* @polarities: Positive or negative polarities
* @pixelclock: Pixel clock in HZ. Ex. 74.25MHz->74250000
* @hfrontporch:Horizontal front porch in pixels
* @hsync:&nbs...
-
-
...hone[12];
char from_date[20];
char to_date[20];
float payment_advance;
int booking_id;
};
class Room
{
public:
char type;
char stype;
char ac;
int roomNumber;
int rent;
int status;
class Customer cust;
class Room addRoom(int);
void searchRoom(int);
void deleteRoom(int);
void dis...
-
-
...的排列后再去掉不满足条件的排列。2.程序源代码：main(){int i,j,k;printf(“\n“);for(i=1;i〈5;i++) ／*以下为三重循环*/ for(j=1;j〈5;j++) for (k=1;k〈5;k++) { if (i!=k&&i!=j&&j!=k) /*确保i、j、k三位...
-
-
...码的选择数组
unsigned char Buffer[10];//Buffer为缓冲区
// long int counter=0;
long int sec=0;
int minute=0;
int hour=0;
long int timer1; //闹钟计时
bit UpdateTimeFlag;
void delay(int time1);//延时函数
void display();//数码管刷新函数
void Init_Timer0(void);//定时...
-
-
#include <stdio.h>int max (int a,int b) { return a > b ? a : b;}struct E{ int w; &...
-
-
...snake.bmp"
#define SUCCESS "./SNK_pic/success.bmp"
int bmp_show(char * pic_path, int x0, int y0);
void lcd_init(void);
void lcd_free(void);
int bmp_show_bck(int x0, int y0, int W, int H);
void get_xy( int * x, int *y);
#endif想了解...
-
-
...索引） 注意点：*/#pragma once#include "../all.h"int binary_search(vector<int>& nums, int v) { if (nums.size() < 1) return - 1; int lo = -1, hi = nums.size(); while (hi - lo > 1) { &n...
