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...atagore':{'$exists':True}, 'is_trained':{'$exists':False}})     if (not artical_tag):         exit(1)     artical = db.artical.find_one({'_id':ObjectId(artical_tag["a_id"])})     with open("../data_spider/html/" + artical['title_hash'] + ".html",...

多机通信

... { uchar scancode,tmpcode; P1 = 0xf0; // 发全0行扫描码 if ((P1&0xf0)!=0xf0) // 若有键按下 { delay(10); // 延时去抖动 if ((P1&0xf0)!=0xf0) // 延时后再判断一次,去除抖动影响 { scancode = 0xfe; while((scancode&0x10...

Linux内核驱动的示例

...r[256]; int simple_open(struct inode *inode, struct file *filp) {  if(simple_inc>0)return -ERESTARTSYS;  simple_inc++;  return 0; } int simple_release(struct inode *inode, struct file *filp) {  simple_inc--;  return 0; } ssize_t simple_read(struct file *filp, ...

JavaScript演示类型数据

...ngzai(1,2); //1;2; chongzai(2);//1;undefined function chongzai(){  if(arguments.length==1){   console.log(arguments[0]);  }else if(arguments.length == 2){   console.log(arguments[0]);   console.log(arguments[1]);  }else{   return false;...

CCF计算机职业资格认证真题题解

...li = input().split()sum=0a = range(len(li))for i in a:    if li[i] == '1':        sum += 1        i += 1    elif li[i] == '2':        n = 2    &n...

opensm源码

...        In the array below, the 2nd parameter specifies the number        of arguments as follows:        0: no arguments        1: argument        2: optional  &nbs...

舞蹈机器人步进机仿真

...speeds[i]; //计数值增加 speed[i]越高,增加得越多     if(speed_tickers[i] >= MAX_SPEED_TICKER) //如果计数值超过预定最大值,就发送脉冲     {       speed_tickers[i] = 0;       delta = 1;     }     ...

linux之pcie驱动

... int ret;  ret = pci_register_driver(&hello_driver);  if (ret < 0) {   printk("failed: pci_register_driver\n");   return ret;  }    ret=alloc_chrdev_region(&my_device.devno,0,DEVICE_NUMBER,"hello");  if (ret < 0) {  &...

酒店管理项

... Room::searchRoom(int rno) { int i,found=0; for(i=0;i<count;i++) { if(rooms[i].roomNumber==rno) { found=1; break; } } if(found==1) { cout<<"Room Details\n"; if(rooms[i].status==1) { cout<<"\nRoom is Reserved"; } else { cout<<"\nRoom is available"; } display...

超大屏幕点阵显示

...t;6;i++)   {yiwei(i,0,k); yiwei(i,1,k); } i=0; k++; if(k>15) k=0;         P2=n; E1=0; ST=1; for(u=0;u<150;u++){} n++; if(n>15) n=0; E1=1; ST=0;         } }

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